Optimal. Leaf size=568 \[ \frac {2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (\frac {1}{2} \left (\frac {3 b}{d}-n\right ),-n;\frac {1}{2} \left (\frac {3 b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (i (3 a-c n)+i x (3 b-d n)+i n (c+d x))}{3 b-d n}-\frac {3\ 2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,\frac {b-d n}{2 d};\frac {1}{2} \left (\frac {b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (i (a-c n)+i x (b-d n)+i n (c+d x))}{b-d n}-\frac {3\ 2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac {b+d n}{2 d};1-\frac {b+d n}{2 d};-e^{2 i (c+d x)}\right ) \exp (-i (a+c n)-i x (b+d n)+i n (c+d x))}{b+d n}+\frac {2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac {3 b+d n}{2 d};\frac {1}{2} \left (-\frac {3 b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (-i (3 a+c n)-i x (3 b+d n)+i n (c+d x))}{3 b+d n} \]
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Rubi [A] time = 1.18, antiderivative size = 568, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 4, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.235, Rules used = {4555, 2285, 2253, 2251} \[ \frac {2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (\frac {1}{2} \left (\frac {3 b}{d}-n\right ),-n;\frac {1}{2} \left (\frac {3 b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (i (3 a-c n)+i x (3 b-d n)+i n (c+d x))}{3 b-d n}-\frac {3\ 2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,\frac {b-d n}{2 d};\frac {1}{2} \left (\frac {b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (i (a-c n)+i x (b-d n)+i n (c+d x))}{b-d n}-\frac {3\ 2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac {b+d n}{2 d};1-\frac {b+d n}{2 d};-e^{2 i (c+d x)}\right ) \exp (-i (a+c n)-i x (b+d n)+i n (c+d x))}{b+d n}+\frac {2^{-n-3} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \left (1+e^{2 i c+2 i d x}\right )^{-n} \, _2F_1\left (-n,-\frac {3 b+d n}{2 d};\frac {1}{2} \left (-\frac {3 b}{d}-n+2\right );-e^{2 i (c+d x)}\right ) \exp (-i (3 a+c n)-i x (3 b+d n)+i n (c+d x))}{3 b+d n} \]
Antiderivative was successfully verified.
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Rule 2251
Rule 2253
Rule 2285
Rule 4555
Rubi steps
\begin {align*} \int \cos ^n(c+d x) \sin ^3(a+b x) \, dx &=2^{-3-n} \int \left (3 i e^{-i a-i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n-3 i e^{i a+i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n-i e^{-3 i a-3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n+i e^{3 i a+3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \, dx\\ &=-\left (\left (i 2^{-3-n}\right ) \int e^{-3 i a-3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx\right )+\left (i 2^{-3-n}\right ) \int e^{3 i a+3 i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx+\left (3 i 2^{-3-n}\right ) \int e^{-i a-i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx-\left (3 i 2^{-3-n}\right ) \int e^{i a+i b x} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, dx\\ &=-\left (\left (i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-3 i a-3 i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx\right )+\left (i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{3 i a+3 i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx+\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-i a-i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx-\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{i a+i b x-i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^n \, dx\\ &=\left (i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{i (3 a-c n)+i (3 b-d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx-\left (i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-i (3 a+c n)-i (3 b+d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx-\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{i (a-c n)+i (b-d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx+\left (3 i 2^{-3-n} e^{i n (c+d x)} \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n\right ) \int e^{-i (a+c n)-i (b+d n) x} \left (1+e^{2 i c+2 i d x}\right )^n \, dx\\ &=\frac {2^{-3-n} \exp (i (3 a-c n)+i (3 b-d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (\frac {1}{2} \left (\frac {3 b}{d}-n\right ),-n;\frac {1}{2} \left (2+\frac {3 b}{d}-n\right );-e^{2 i (c+d x)}\right )}{3 b-d n}-\frac {3\ 2^{-3-n} \exp (i (a-c n)+i (b-d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (-n,\frac {b-d n}{2 d};\frac {1}{2} \left (2+\frac {b}{d}-n\right );-e^{2 i (c+d x)}\right )}{b-d n}-\frac {3\ 2^{-3-n} \exp (-i (a+c n)-i (b+d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (-n,-\frac {b+d n}{2 d};1-\frac {b+d n}{2 d};-e^{2 i (c+d x)}\right )}{b+d n}+\frac {2^{-3-n} \exp (-i (3 a+c n)-i (3 b+d n) x+i n (c+d x)) \left (1+e^{2 i c+2 i d x}\right )^{-n} \left (e^{-i (c+d x)}+e^{i (c+d x)}\right )^n \, _2F_1\left (-n,-\frac {3 b+d n}{2 d};\frac {1}{2} \left (2-\frac {3 b}{d}-n\right );-e^{2 i (c+d x)}\right )}{3 b+d n}\\ \end {align*}
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Mathematica [A] time = 23.94, size = 329, normalized size = 0.58 \[ 2^{-n-3} \left (e^{-i (c+d x)} \left (1+e^{2 i (c+d x)}\right )\right )^{n+1} e^{i (-3 a+c+d (n+1) x)} \left (-\frac {3 e^{2 i a-i x (b+d n)} \, _2F_1\left (1,\frac {1}{2} \left (-\frac {b}{d}+n+2\right );-\frac {b+d (n-2)}{2 d};-e^{2 i (c+d x)}\right )}{b+d n}+e^{i (4 a+b x-d n x)} \left (\frac {e^{2 i (a+b x)} \, _2F_1\left (1,\frac {1}{2} \left (\frac {3 b}{d}+n+2\right );\frac {3 b}{2 d}-\frac {n}{2}+1;-e^{2 i (c+d x)}\right )}{3 b-d n}-\frac {3 \, _2F_1\left (1,\frac {b+d (n+2)}{2 d};\frac {1}{2} \left (\frac {b}{d}-n+2\right );-e^{2 i (c+d x)}\right )}{b-d n}\right )+\frac {e^{-i x (3 b+d n)} \, _2F_1\left (1,\frac {1}{2} \left (-\frac {3 b}{d}+n+2\right );-\frac {3 b}{2 d}-\frac {n}{2}+1;-e^{2 i (c+d x)}\right )}{3 b+d n}\right ) \]
Warning: Unable to verify antiderivative.
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fricas [F] time = 0.54, size = 0, normalized size = 0.00 \[ {\rm integral}\left (-{\left (\cos \left (b x + a\right )^{2} - 1\right )} \cos \left (d x + c\right )^{n} \sin \left (b x + a\right ), x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \cos \left (d x + c\right )^{n} \sin \left (b x + a\right )^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [F] time = 5.52, size = 0, normalized size = 0.00 \[ \int \left (\cos ^{n}\left (d x +c \right )\right ) \left (\sin ^{3}\left (b x +a \right )\right )\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \cos \left (d x + c\right )^{n} \sin \left (b x + a\right )^{3}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int {\cos \left (c+d\,x\right )}^n\,{\sin \left (a+b\,x\right )}^3 \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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